fluent-uri

A full-featured URI handling library compliant with RFC 3986. It is:

• Fast: Zero-copy parsing. Benchmarked to be highly performant.¹
• Easy: Carefully designed and documented APIs. Handy percent-encoding utilities.
• Correct: Forbids unsafe code. Extensively fuzz-tested against other implementations.

Documentation | Discussions

Examples

• Uri<&str> and Uri<String> (borrowed and owned variants of URI reference):

  You can parse into a Uri<&str> from a string slice. Uri<&'a str> outputs references with lifetime 'a where possible (thanks to borrow-or-share):

  // Keep a reference to the path after dropping the `Uri`.
  let path = Uri::parse("foo:bar")?.path();
  assert_eq!(path, "bar");

  You can build a Uri<String> using the builder pattern:

  const SCHEME_FOO: &Scheme = Scheme::new_or_panic("foo");
  
  let uri: Uri<String> = Uri::builder()
      .scheme(SCHEME_FOO)
      .authority(|b| {
          b.userinfo(EStr::new_or_panic("user"))
              .host(EStr::new_or_panic("example.com"))
              .port(8042)
      })
      .path(EStr::new_or_panic("/over/there"))
      .query(EStr::new_or_panic("name=ferret"))
      .fragment(EStr::new_or_panic("nose"))
      .build()
      .unwrap();
  
  assert_eq!(
      uri.as_str(),
      "foo://user@example.com:8042/over/there?name=ferret#nose"
  );

  You can resolve a URI reference against a base URI:

  let base = Uri::parse("http://example.com/foo/bar")?;
  
  assert_eq!(Uri::parse("baz")?.resolve_against(&base)?, "http://example.com/foo/baz");
  assert_eq!(Uri::parse("../baz")?.resolve_against(&base)?, "http://example.com/baz");
  assert_eq!(Uri::parse("?baz")?.resolve_against(&base)?, "http://example.com/foo/bar?baz");

  You can normalize a URI reference:

  let uri = Uri::parse("eXAMPLE://a/./b/../b/%63/%7bfoo%7d")?;
  assert_eq!(uri.normalize(), "example://a/b/c/%7Bfoo%7D");

• EStr (Percent-encoded string slices):

  All components in a URI that may be percent-encoded are parsed as EStrs, which allows easy splitting and decoding:

  let query = "name=%E5%BC%A0%E4%B8%89&speech=%C2%A1Ol%C3%A9%21";
  let map: HashMap<_, _> = EStr::<Query>::new_or_panic(query)
      .split('&')
      .map(|s| s.split_once('=').unwrap_or((s, EStr::EMPTY)))
      .map(|(k, v)| (k.decode().into_string_lossy(), v.decode().into_string_lossy()))
      .collect();
  assert_eq!(map["name"], "张三");
  assert_eq!(map["speech"], "¡Olé!");

• EString (A percent-encoded, growable string):

  You can encode key-value pairs to a query string and use it to build a Uri:

  let pairs = [("name", "张三"), ("speech", "¡Olé!")];
  let mut buf = EString::<Query>::new();
  for (k, v) in pairs {
      if !buf.is_empty() {
          buf.push_byte(b'&');
      }
      buf.encode::<Data>(k);
      buf.push_byte(b'=');
      buf.encode::<Data>(v);
  }
  
  assert_eq!(buf, "name=%E5%BC%A0%E4%B8%89&speech=%C2%A1Ol%C3%A9%21");
  
  let uri = Uri::builder()
      .path(EStr::new_or_panic(""))
      .query(&buf)
      .build();
  assert_eq!(uri.as_str(), "?name=%E5%BC%A0%E4%B8%89&speech=%C2%A1Ol%C3%A9%21");

Footnotes

1. In a benchmark on an Intel Core i5-11300H processor, fluent-uri parsed a URI in 49ns compared to 89ns for iref and 135ns for iri-string. ↩