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Extract .zip files with recorded file timestamps (#15268) #15269

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Extract .zip files with recorded file timestamps (#15268) #15269

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9 changes: 8 additions & 1 deletion conan/tools/files/files.py
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Expand Up @@ -4,6 +4,7 @@
import shutil
import subprocess
import sys
import time
from contextlib import contextmanager
from fnmatch import fnmatch
from shutil import which
Expand Down Expand Up @@ -341,18 +342,24 @@ def print_progress(_, __):
except Exception as e:
output.error(f"Error extract {file_.filename}\n{str(e)}", error_type="exception")
else: # duplicated for, to avoid a platform check for each zipped file
file_timestamps = []
for file_ in zip_info:
extracted_size += file_.file_size
print_progress(extracted_size, uncompress_size)
try:
z.extract(file_, full_path)
file_path = os.path.join(full_path, file_.filename)
ts = time.mktime(file_.date_time + (0, 0, -1))
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Why this 0, 0, -1? This would need some comment

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file_.date_time provides six timestamp fields, but time.mktime() needs three additional fields to make a struct_time.

I can add a comment to this effect.

file_timestamps.append((file_path, ts))
if keep_permissions:
# Could be dangerous if the ZIP has been created in a non nix system
# https://bugs.python.org/issue15795
perm = file_.external_attr >> 16 & 0xFFF
os.chmod(os.path.join(full_path, file_.filename), perm)
os.chmod(file_path, perm)
except Exception as e:
output.error(f"Error extract {file_.filename}\n{str(e)}", error_type="exception")
for file_path, ts in file_timestamps:
os.utime(file_path, (ts, ts))
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Why the z.extract() will not automatically handle the zip timestamp? It doesn't make much sense that this has to be handled manually?

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Beats me. Seems like quite the oversight for the API.

Apparently not even .extractall() gets you that.

output.writeln("")


Expand Down