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docs: infer Literal from the schema in JSON type example #1083

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merged 1 commit into from Apr 14, 2022
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docs: infer Literal from the schema in JSON type example #1083

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4 changes: 2 additions & 2 deletions README.md
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Expand Up @@ -1185,9 +1185,9 @@ const Category: z.ZodType<Category> = BaseCategory.merge(
If you want to validate any JSON value, you can use the snippet below.

```ts
type Literal = boolean | null | number | string;
type Json = Literal | { [key: string]: Json } | Json[];
const literalSchema = z.union([z.string(), z.number(), z.boolean(), z.null()]);
type Literal = z.infer<typeof literalSchema>;
type Json = Literal | { [key: string]: Json } | Json[];
const jsonSchema: z.ZodType<Json> = z.lazy(() =>
z.union([literalSchema, z.array(jsonSchema), z.record(jsonSchema)])
);
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4 changes: 2 additions & 2 deletions README_ZH.md
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Expand Up @@ -1012,9 +1012,9 @@ const Category: z.ZodSchema<Category> = BaseCategory.merge(
如果你想验证任何 JSON 值，你可以使用下面的片段。

```ts
type Literal = boolean | null | number | string;
type Json = Literal | { [key: string]: Json } | Json[];
const literalSchema = z.union([z.string(), z.number(), z.boolean(), z.null()]);
type Literal = z.infer<typeof literalSchema>;
type Json = Literal | { [key: string]: Json } | Json[];
const jsonSchema: z.ZodSchema<Json> = z.lazy(() =>
z.union([literalSchema, z.array(jsonSchema), z.record(jsonSchema)])
);
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