pass reloader tests

python doesn't have an obvious way to reveal the original command and module name, so we check the __main__ module for __package__ and infer it's a module running as a script unless the value is None, which implies a file path was provided
modules running as scripts are invoked with -m flags
packages running with scripts have base filename __main__.py
from this we recreate an invocation

bottle.py

@@ -3633,6 +3633,14 @@ def load_app(target):
 
 _debug = debug
 
+def _main_module_name():
+    package = vars(sys.modules['__main__'])['__package__']
+    if package is None:
+        return None
+    else:
+        file_path = sys.argv[0]
+        base_name, _ = os.path.splitext(os.path.basename(file_path))
+        return package if base_name == '__main__' else '.'.join((package, base_name))
 
 def run(app=None,
         server='wsgiref',
@@ -3667,11 +3675,13 @@ def run(app=None,
         try:
             fd, lockfile = tempfile.mkstemp(prefix='bottle.', suffix='.lock')
             os.close(fd)  # We only need this file to exist. We never write to it
+            module_name = _main_module_name()
+            options = [sys.argv[0]] if module_name is None else ['-m', module_name]
+            args = [sys.executable] + options + sys.argv[1:]
+            environ = os.environ.copy()
+            environ['BOTTLE_CHILD'] = 'true'
+            environ['BOTTLE_LOCKFILE'] = lockfile
             while os.path.exists(lockfile):
-                args = [sys.executable] + sys.argv
-                environ = os.environ.copy()
-                environ['BOTTLE_CHILD'] = 'true'
-                environ['BOTTLE_LOCKFILE'] = lockfile
                 p = subprocess.Popen(args, env=environ)
                 while p.poll() is None:  # Busy wait...
                     os.utime(lockfile, None)  # I am alive!