Skip to content

Latest commit

 

History

History
378 lines (328 loc) · 18.8 KB

README.rst

File metadata and controls

378 lines (328 loc) · 18.8 KB
Raw

Github

Version

Downloads

GitHub Actions Unittests

Coveralls

License

GitHub Actions Linters

Black formatted

Looks Good To Me

A simple web scraping tool for recipe sites.

pip install recipe-scrapers

then:

from recipe_scrapers import scrape_me

# give the url as a string, it can be url from any site listed below
scraper = scrape_me('https://www.allrecipes.com/recipe/158968/spinach-and-feta-turkey-burgers/')

# Q: What if the recipe site I want to extract information from is not listed below?
# A: You can give it a try with the wild_mode option! If there is Schema/Recipe available it will work just fine.
scraper = scrape_me('https://www.feastingathome.com/tomato-risotto/', wild_mode=True)

scraper.title()
scraper.total_time()
scraper.yields()
scraper.ingredients()
scraper.instructions()  # or alternatively for results as a Python list: scraper.instructions_list()
scraper.image()
scraper.host()
scraper.links()
scraper.nutrients()  # if available

# Starting from version 14.0.0 you also have an option to scrape from html-like content
import requests
from recipe_scrapers import scrape_html

url = "https://www.allrecipes.com/recipe/158968/spinach-and-feta-turkey-burgers/"
html = requests.get(url).content

scraper = scrape_html(html=html, org_url=url)

scraper.title()
scraper.total_time()
# etc...

Notes:

  • scraper.links() returns a list of dictionaries containing all of the <a> tag attributes. The attribute names are the dictionary keys.

Scrapers available for:

Contribute

If you spot a design change (or something else) that makes the scraper unable to work for a given site - please fire an issue asap.

If you are programmer PRs with fixes are warmly welcomed and acknowledged with a virtual beer.

If you want a scraper for a new site added

  • Open an Issue providing us the site name, as well as a recipe link from it.
  • You are a developer and want to code the scraper on your own:
    • If Schema is available on the site - you can go like this.
    • Otherwise, scrape the HTML - like this

    • Generating a new scraper class:

      python generate.py <ClassName> <URL>
      • ClassName: The name of the new scraper class.
      • URL: The URL of an example recipe from the target site. The content will be stored in test_data to be used with the test class.

For Devs / Contribute

Assuming you have >=python3.7 installed, navigate to the directory where you want this project to live in and drop these lines

git clone git@github.com:hhursev/recipe-scrapers.git &&
cd recipe-scrapers &&
python3 -m venv .venv &&
source .venv/bin/activate &&
pip install -r requirements-dev.txt &&
pre-commit install &&
python run_tests.py

In case you want to run a single unittest for a newly developed scraper

python -m coverage run -m unittest tests.test_myscraper

FAQ

  • How do I know if a website has a Recipe Schema? Run in python shell:
from recipe_scrapers import scrape_me
scraper = scrape_me('<url of a recipe from the site>', wild_mode=True)
# if no error is raised - there's schema available:
scraper.title()
scraper.instructions()  # etc.

Netiquette

If you're using this library to collect large numbers of recipes from the web, please use the software responsibly and try to avoid creating high volumes of network traffic.

Python's standard library provides a robots.txt parser that may be helpful to automatically follow common instructions specified by websites for web crawlers.

Another parser option -- particularly if you find that many web requests from urllib.robotparser are blocked -- is the robotsexclusionparser library.

Special thanks to:

All the contributors that helped improving the package. You are awesome!