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Backtick operator does not mark variable as used #6367

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danog opened this issue Aug 26, 2021 · 1 comment · Fixed by #6376

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bug

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danog commented Aug 26, 2021

https://psalm.dev/r/580997aa9a

psalm-github-bot bot commented Aug 26, 2021

I found these snippets:

https://psalm.dev/r/580997aa9a

<?php
$used = 'echo';
`$used`;

$used = 'echo';
shell_exec($used);

Psalm output (using commit 9222b24):

ERROR: ForbiddenCode - 3:1 - Use of shell_exec

ERROR: ForbiddenCode - 6:1 - Unsafe shell_exec

INFO: UnusedVariable - 2:1 - $used is never referenced or the value is not used

weirdan added the bug label

orklah mentioned this issue

Use variable in backtick #6376

Merged

weirdan closed this as completed in #6376

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