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The shapely.ops.substring() function fails if not all vertices of the LineString have a Z coordinate (which stems from some operations like segmentize() losing Z, but I guess that's a GEOS issue).
The shapely.ops.substring() function fails if not all vertices of the LineString have a Z coordinate (which stems from some operations like segmentize() losing Z, but I guess that's a GEOS issue).
Steps to reproduce the problem.
Error
Operating system
Ubuntu 22.04
Shapely version and provenance
shapely 2.0.3 installed from PyPI using pip
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