/
bitfield_unit_tests.rs
260 lines (214 loc) · 8.01 KB
/
bitfield_unit_tests.rs
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//! Tests for `__BindgenBitfieldUnit`.
//!
//! Note that bit-fields are allocated right to left (least to most significant
//! bits).
//!
//! From the x86 PS ABI:
//!
//! ```c
//! struct {
//! int j : 5;
//! int k : 6;
//! int m : 7;
//! };
//! ```
//!
//! ```ignore
//! +------------------------------------------------------------+
//! | | | | |
//! | padding | m | k | j |
//! |31 18|17 11|10 5|4 0|
//! +------------------------------------------------------------+
//! ```
use super::bitfield_unit::__BindgenBitfieldUnit;
#[test]
fn bitfield_unit_get_bit() {
let unit = __BindgenBitfieldUnit::<[u8; 2]>::new([0b10011101, 0b00011101]);
let mut bits = vec![];
for i in 0..16 {
bits.push(unit.get_bit(i));
}
println!();
println!("bits = {:?}", bits);
assert_eq!(
bits,
&[
// 0b10011101
true, false, true, true, true, false, false, true,
// 0b00011101
true, false, true, true, true, false, false, false
]
);
}
#[test]
fn bitfield_unit_set_bit() {
let mut unit =
__BindgenBitfieldUnit::<[u8; 2]>::new([0b00000000, 0b00000000]);
for i in 0..16 {
if i % 3 == 0 {
unit.set_bit(i, true);
}
}
for i in 0..16 {
assert_eq!(unit.get_bit(i), i % 3 == 0);
}
let mut unit =
__BindgenBitfieldUnit::<[u8; 2]>::new([0b11111111, 0b11111111]);
for i in 0..16 {
if i % 3 == 0 {
unit.set_bit(i, false);
}
}
for i in 0..16 {
assert_eq!(unit.get_bit(i), i % 3 != 0);
}
}
macro_rules! bitfield_unit_get {
(
$(
With $storage:expr , then get($start:expr, $len:expr) is $expected:expr;
)*
) => {
#[test]
fn bitfield_unit_get() {
$({
let expected = $expected;
let unit = __BindgenBitfieldUnit::<_>::new($storage);
let actual = unit.get($start, $len);
println!();
println!("expected = {:064b}", expected);
println!("actual = {:064b}", actual);
assert_eq!(expected, actual);
})*
}
}
}
bitfield_unit_get! {
// Let's just exhaustively test getting the bits from a single byte, since
// there are few enough combinations...
With [0b11100010], then get(0, 1) is 0;
With [0b11100010], then get(1, 1) is 1;
With [0b11100010], then get(2, 1) is 0;
With [0b11100010], then get(3, 1) is 0;
With [0b11100010], then get(4, 1) is 0;
With [0b11100010], then get(5, 1) is 1;
With [0b11100010], then get(6, 1) is 1;
With [0b11100010], then get(7, 1) is 1;
With [0b11100010], then get(0, 2) is 0b10;
With [0b11100010], then get(1, 2) is 0b01;
With [0b11100010], then get(2, 2) is 0b00;
With [0b11100010], then get(3, 2) is 0b00;
With [0b11100010], then get(4, 2) is 0b10;
With [0b11100010], then get(5, 2) is 0b11;
With [0b11100010], then get(6, 2) is 0b11;
With [0b11100010], then get(0, 3) is 0b010;
With [0b11100010], then get(1, 3) is 0b001;
With [0b11100010], then get(2, 3) is 0b000;
With [0b11100010], then get(3, 3) is 0b100;
With [0b11100010], then get(4, 3) is 0b110;
With [0b11100010], then get(5, 3) is 0b111;
With [0b11100010], then get(0, 4) is 0b0010;
With [0b11100010], then get(1, 4) is 0b0001;
With [0b11100010], then get(2, 4) is 0b1000;
With [0b11100010], then get(3, 4) is 0b1100;
With [0b11100010], then get(4, 4) is 0b1110;
With [0b11100010], then get(0, 5) is 0b00010;
With [0b11100010], then get(1, 5) is 0b10001;
With [0b11100010], then get(2, 5) is 0b11000;
With [0b11100010], then get(3, 5) is 0b11100;
With [0b11100010], then get(0, 6) is 0b100010;
With [0b11100010], then get(1, 6) is 0b110001;
With [0b11100010], then get(2, 6) is 0b111000;
With [0b11100010], then get(0, 7) is 0b1100010;
With [0b11100010], then get(1, 7) is 0b1110001;
With [0b11100010], then get(0, 8) is 0b11100010;
// OK. Now let's test getting bits from across byte boundaries.
With [0b01010101, 0b11111111, 0b00000000, 0b11111111],
then get(0, 16) is 0b1111111101010101;
With [0b01010101, 0b11111111, 0b00000000, 0b11111111],
then get(1, 16) is 0b0111111110101010;
With [0b01010101, 0b11111111, 0b00000000, 0b11111111],
then get(2, 16) is 0b0011111111010101;
With [0b01010101, 0b11111111, 0b00000000, 0b11111111],
then get(3, 16) is 0b0001111111101010;
With [0b01010101, 0b11111111, 0b00000000, 0b11111111],
then get(4, 16) is 0b0000111111110101;
With [0b01010101, 0b11111111, 0b00000000, 0b11111111],
then get(5, 16) is 0b0000011111111010;
With [0b01010101, 0b11111111, 0b00000000, 0b11111111],
then get(6, 16) is 0b0000001111111101;
With [0b01010101, 0b11111111, 0b00000000, 0b11111111],
then get(7, 16) is 0b0000000111111110;
With [0b01010101, 0b11111111, 0b00000000, 0b11111111],
then get(8, 16) is 0b0000000011111111;
}
macro_rules! bitfield_unit_set {
(
$(
set($start:expr, $len:expr, $val:expr) is $expected:expr;
)*
) => {
#[test]
fn bitfield_unit_set() {
$(
let mut unit = __BindgenBitfieldUnit::<[u8; 4]>::new([0, 0, 0, 0]);
unit.set($start, $len, $val);
let actual = unit.get(0, 32);
println!();
println!("set({}, {}, {:032b}", $start, $len, $val);
println!("expected = {:064b}", $expected);
println!("actual = {:064b}", actual);
assert_eq!($expected, actual);
)*
}
}
}
bitfield_unit_set! {
// Once again, let's exhaustively test single byte combinations.
set(0, 1, 0b11111111) is 0b00000001;
set(1, 1, 0b11111111) is 0b00000010;
set(2, 1, 0b11111111) is 0b00000100;
set(3, 1, 0b11111111) is 0b00001000;
set(4, 1, 0b11111111) is 0b00010000;
set(5, 1, 0b11111111) is 0b00100000;
set(6, 1, 0b11111111) is 0b01000000;
set(7, 1, 0b11111111) is 0b10000000;
set(0, 2, 0b11111111) is 0b00000011;
set(1, 2, 0b11111111) is 0b00000110;
set(2, 2, 0b11111111) is 0b00001100;
set(3, 2, 0b11111111) is 0b00011000;
set(4, 2, 0b11111111) is 0b00110000;
set(5, 2, 0b11111111) is 0b01100000;
set(6, 2, 0b11111111) is 0b11000000;
set(0, 3, 0b11111111) is 0b00000111;
set(1, 3, 0b11111111) is 0b00001110;
set(2, 3, 0b11111111) is 0b00011100;
set(3, 3, 0b11111111) is 0b00111000;
set(4, 3, 0b11111111) is 0b01110000;
set(5, 3, 0b11111111) is 0b11100000;
set(0, 4, 0b11111111) is 0b00001111;
set(1, 4, 0b11111111) is 0b00011110;
set(2, 4, 0b11111111) is 0b00111100;
set(3, 4, 0b11111111) is 0b01111000;
set(4, 4, 0b11111111) is 0b11110000;
set(0, 5, 0b11111111) is 0b00011111;
set(1, 5, 0b11111111) is 0b00111110;
set(2, 5, 0b11111111) is 0b01111100;
set(3, 5, 0b11111111) is 0b11111000;
set(0, 6, 0b11111111) is 0b00111111;
set(1, 6, 0b11111111) is 0b01111110;
set(2, 6, 0b11111111) is 0b11111100;
set(0, 7, 0b11111111) is 0b01111111;
set(1, 7, 0b11111111) is 0b11111110;
set(0, 8, 0b11111111) is 0b11111111;
// And, now let's cross byte boundaries.
set(0, 16, 0b1111111111111111) is 0b00000000000000001111111111111111;
set(1, 16, 0b1111111111111111) is 0b00000000000000011111111111111110;
set(2, 16, 0b1111111111111111) is 0b00000000000000111111111111111100;
set(3, 16, 0b1111111111111111) is 0b00000000000001111111111111111000;
set(4, 16, 0b1111111111111111) is 0b00000000000011111111111111110000;
set(5, 16, 0b1111111111111111) is 0b00000000000111111111111111100000;
set(6, 16, 0b1111111111111111) is 0b00000000001111111111111111000000;
set(7, 16, 0b1111111111111111) is 0b00000000011111111111111110000000;
set(8, 16, 0b1111111111111111) is 0b00000000111111111111111100000000;
}