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I was trying to do lazy pool initialization
This is executed every time we need a connection, and it sometimes lead to
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Answered by
dvarrazzo
Feb 23, 2023
Replies: 1 comment 4 replies
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Opening it the second time should be idempotent. But you are probably calling open a second time before the open at the first time has finished. This is not supported. open can be called more than once, but not concurrently. |
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Answer selected by
sjiekak
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Opening it the second time should be idempotent. But you are probably calling open a second time before the open at the first time has finished.
This is not supported. open can be called more than once, but not concurrently.