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{{ header }}

Group by: split-apply-combine

By "group by" we are referring to a process involving one or more of the following steps:

  • Splitting the data into groups based on some criteria.
  • Applying a function to each group independently.
  • Combining the results into a data structure.

Out of these, the split step is the most straightforward. In fact, in many situations we may wish to split the data set into groups and do something with those groups. In the apply step, we might wish to do one of the following:

  • Aggregation: compute a summary statistic (or statistics) for each group. Some examples:

    • Compute group sums or means.
    • Compute group sizes / counts.
  • Transformation: perform some group-specific computations and return a like-indexed object. Some examples:

    • Standardize data (zscore) within a group.
    • Filling NAs within groups with a value derived from each group.
  • Filtration: discard some groups, according to a group-wise computation that evaluates True or False. Some examples:

    • Discard data that belongs to groups with only a few members.
    • Filter out data based on the group sum or mean.
  • Some combination of the above: GroupBy will examine the results of the apply step and try to return a sensibly combined result if it doesn't fit into either of the above two categories.

Since the set of object instance methods on pandas data structures are generally rich and expressive, we often simply want to invoke, say, a DataFrame function on each group. The name GroupBy should be quite familiar to those who have used a SQL-based tool (or itertools), in which you can write code like:

SELECT Column1, Column2, mean(Column3), sum(Column4)
FROM SomeTable
GROUP BY Column1, Column2

We aim to make operations like this natural and easy to express using pandas. We'll address each area of GroupBy functionality then provide some non-trivial examples / use cases.

See the :ref:`cookbook<cookbook.grouping>` for some advanced strategies.

Splitting an object into groups

pandas objects can be split on any of their axes. The abstract definition of grouping is to provide a mapping of labels to group names. To create a GroupBy object (more on what the GroupBy object is later), you may do the following:

.. ipython:: python

    df = pd.DataFrame(
        [
            ("bird", "Falconiformes", 389.0),
            ("bird", "Psittaciformes", 24.0),
            ("mammal", "Carnivora", 80.2),
            ("mammal", "Primates", np.nan),
            ("mammal", "Carnivora", 58),
        ],
        index=["falcon", "parrot", "lion", "monkey", "leopard"],
        columns=("class", "order", "max_speed"),
    )
    df

    # default is axis=0
    grouped = df.groupby("class")
    grouped = df.groupby("order", axis="columns")
    grouped = df.groupby(["class", "order"])

The mapping can be specified many different ways:

  • A Python function, to be called on each of the axis labels.
  • A list or NumPy array of the same length as the selected axis.
  • A dict or Series, providing a label -> group name mapping.
  • For DataFrame objects, a string indicating either a column name or an index level name to be used to group.
  • df.groupby('A') is just syntactic sugar for df.groupby(df['A']).
  • A list of any of the above things.

Collectively we refer to the grouping objects as the keys. For example, consider the following DataFrame:

Note

A string passed to groupby may refer to either a column or an index level. If a string matches both a column name and an index level name, a ValueError will be raised.

.. ipython:: python

   df = pd.DataFrame(
       {
           "A": ["foo", "bar", "foo", "bar", "foo", "bar", "foo", "foo"],
           "B": ["one", "one", "two", "three", "two", "two", "one", "three"],
           "C": np.random.randn(8),
           "D": np.random.randn(8),
       }
   )
   df

On a DataFrame, we obtain a GroupBy object by calling :meth:`~DataFrame.groupby`. We could naturally group by either the A or B columns, or both:

.. ipython:: python

   grouped = df.groupby("A")
   grouped = df.groupby(["A", "B"])

If we also have a MultiIndex on columns A and B, we can group by all but the specified columns

.. ipython:: python

   df2 = df.set_index(["A", "B"])
   grouped = df2.groupby(level=df2.index.names.difference(["B"]))
   grouped.sum()

These will split the DataFrame on its index (rows). We could also split by the columns:

.. ipython::

    In [4]: def get_letter_type(letter):
       ...:     if letter.lower() in 'aeiou':
       ...:         return 'vowel'
       ...:     else:
       ...:         return 'consonant'
       ...:

    In [5]: grouped = df.groupby(get_letter_type, axis=1)

pandas :class:`~pandas.Index` objects support duplicate values. If a non-unique index is used as the group key in a groupby operation, all values for the same index value will be considered to be in one group and thus the output of aggregation functions will only contain unique index values:

.. ipython:: python

   lst = [1, 2, 3, 1, 2, 3]

   s = pd.Series([1, 2, 3, 10, 20, 30], lst)

   grouped = s.groupby(level=0)

   grouped.first()

   grouped.last()

   grouped.sum()

Note that no splitting occurs until it's needed. Creating the GroupBy object only verifies that you've passed a valid mapping.

Note

Many kinds of complicated data manipulations can be expressed in terms of GroupBy operations (though can't be guaranteed to be the most efficient). You can get quite creative with the label mapping functions.

GroupBy sorting

By default the group keys are sorted during the groupby operation. You may however pass sort=False for potential speedups:

.. ipython:: python

   df2 = pd.DataFrame({"X": ["B", "B", "A", "A"], "Y": [1, 2, 3, 4]})
   df2.groupby(["X"]).sum()
   df2.groupby(["X"], sort=False).sum()


Note that groupby will preserve the order in which observations are sorted within each group. For example, the groups created by groupby() below are in the order they appeared in the original DataFrame:

.. ipython:: python

   df3 = pd.DataFrame({"X": ["A", "B", "A", "B"], "Y": [1, 4, 3, 2]})
   df3.groupby(["X"]).get_group("A")

   df3.groupby(["X"]).get_group("B")


.. versionadded:: 1.1.0

GroupBy dropna

By default NA values are excluded from group keys during the groupby operation. However, in case you want to include NA values in group keys, you could pass dropna=False to achieve it.

.. ipython:: python

    df_list = [[1, 2, 3], [1, None, 4], [2, 1, 3], [1, 2, 2]]
    df_dropna = pd.DataFrame(df_list, columns=["a", "b", "c"])

    df_dropna

.. ipython:: python

    # Default ``dropna`` is set to True, which will exclude NaNs in keys
    df_dropna.groupby(by=["b"], dropna=True).sum()

    # In order to allow NaN in keys, set ``dropna`` to False
    df_dropna.groupby(by=["b"], dropna=False).sum()

The default setting of dropna argument is True which means NA are not included in group keys.

GroupBy object attributes

The groups attribute is a dict whose keys are the computed unique groups and corresponding values being the axis labels belonging to each group. In the above example we have:

.. ipython:: python

   df.groupby("A").groups
   df.groupby(get_letter_type, axis=1).groups

Calling the standard Python len function on the GroupBy object just returns the length of the groups dict, so it is largely just a convenience:

.. ipython:: python

   grouped = df.groupby(["A", "B"])
   grouped.groups
   len(grouped)


GroupBy will tab complete column names (and other attributes):

.. ipython:: python
   :suppress:

   n = 10
   weight = np.random.normal(166, 20, size=n)
   height = np.random.normal(60, 10, size=n)
   time = pd.date_range("1/1/2000", periods=n)
   gender = np.random.choice(["male", "female"], size=n)
   df = pd.DataFrame(
       {"height": height, "weight": weight, "gender": gender}, index=time
   )

.. ipython:: python

   df
   gb = df.groupby("gender")


.. ipython::

   @verbatim
   In [1]: gb.<TAB>  # noqa: E225, E999
   gb.agg        gb.boxplot    gb.cummin     gb.describe   gb.filter     gb.get_group  gb.height     gb.last       gb.median     gb.ngroups    gb.plot       gb.rank       gb.std        gb.transform
   gb.aggregate  gb.count      gb.cumprod    gb.dtype      gb.first      gb.groups     gb.hist       gb.max        gb.min        gb.nth        gb.prod       gb.resample   gb.sum        gb.var
   gb.apply      gb.cummax     gb.cumsum     gb.fillna     gb.gender     gb.head       gb.indices    gb.mean       gb.name       gb.ohlc       gb.quantile   gb.size       gb.tail       gb.weight

GroupBy with MultiIndex

With :ref:`hierarchically-indexed data <advanced.hierarchical>`, it's quite natural to group by one of the levels of the hierarchy.

Let's create a Series with a two-level MultiIndex.

.. ipython:: python


   arrays = [
       ["bar", "bar", "baz", "baz", "foo", "foo", "qux", "qux"],
       ["one", "two", "one", "two", "one", "two", "one", "two"],
   ]
   index = pd.MultiIndex.from_arrays(arrays, names=["first", "second"])
   s = pd.Series(np.random.randn(8), index=index)
   s

We can then group by one of the levels in s.

.. ipython:: python

   grouped = s.groupby(level=0)
   grouped.sum()

If the MultiIndex has names specified, these can be passed instead of the level number:

.. ipython:: python

   s.groupby(level="second").sum()

Grouping with multiple levels is supported.

.. ipython:: python
   :suppress:

   arrays = [
       ["bar", "bar", "baz", "baz", "foo", "foo", "qux", "qux"],
       ["doo", "doo", "bee", "bee", "bop", "bop", "bop", "bop"],
       ["one", "two", "one", "two", "one", "two", "one", "two"],
   ]
   tuples = list(zip(*arrays))
   index = pd.MultiIndex.from_tuples(tuples, names=["first", "second", "third"])
   s = pd.Series(np.random.randn(8), index=index)

.. ipython:: python

   s
   s.groupby(level=["first", "second"]).sum()

Index level names may be supplied as keys.

.. ipython:: python

   s.groupby(["first", "second"]).sum()

More on the sum function and aggregation later.

Grouping DataFrame with Index levels and columns

A DataFrame may be grouped by a combination of columns and index levels by specifying the column names as strings and the index levels as pd.Grouper objects.

.. ipython:: python

   arrays = [
       ["bar", "bar", "baz", "baz", "foo", "foo", "qux", "qux"],
       ["one", "two", "one", "two", "one", "two", "one", "two"],
   ]

   index = pd.MultiIndex.from_arrays(arrays, names=["first", "second"])

   df = pd.DataFrame({"A": [1, 1, 1, 1, 2, 2, 3, 3], "B": np.arange(8)}, index=index)

   df

The following example groups df by the second index level and the A column.

.. ipython:: python

   df.groupby([pd.Grouper(level=1), "A"]).sum()

Index levels may also be specified by name.

.. ipython:: python

   df.groupby([pd.Grouper(level="second"), "A"]).sum()

Index level names may be specified as keys directly to groupby.

.. ipython:: python

   df.groupby(["second", "A"]).sum()

DataFrame column selection in GroupBy

Once you have created the GroupBy object from a DataFrame, you might want to do something different for each of the columns. Thus, using [] similar to getting a column from a DataFrame, you can do:

.. ipython:: python

   df = pd.DataFrame(
       {
           "A": ["foo", "bar", "foo", "bar", "foo", "bar", "foo", "foo"],
           "B": ["one", "one", "two", "three", "two", "two", "one", "three"],
           "C": np.random.randn(8),
           "D": np.random.randn(8),
       }
   )

   df

   grouped = df.groupby(["A"])
   grouped_C = grouped["C"]
   grouped_D = grouped["D"]

This is mainly syntactic sugar for the alternative and much more verbose:

.. ipython:: python

   df["C"].groupby(df["A"])

Additionally this method avoids recomputing the internal grouping information derived from the passed key.

Iterating through groups

With the GroupBy object in hand, iterating through the grouped data is very natural and functions similarly to :py:func:`itertools.groupby`:

.. ipython::

   In [4]: grouped = df.groupby('A')

   In [5]: for name, group in grouped:
      ...:     print(name)
      ...:     print(group)
      ...:

In the case of grouping by multiple keys, the group name will be a tuple:

.. ipython::

   In [5]: for name, group in df.groupby(['A', 'B']):
      ...:     print(name)
      ...:     print(group)
      ...:

See :ref:`timeseries.iterating-label`.

Selecting a group

A single group can be selected using :meth:`~pandas.core.groupby.DataFrameGroupBy.get_group`:

.. ipython:: python

   grouped.get_group("bar")

Or for an object grouped on multiple columns:

.. ipython:: python

   df.groupby(["A", "B"]).get_group(("bar", "one"))

Aggregation

Once the GroupBy object has been created, several methods are available to perform a computation on the grouped data. These operations are similar to the :ref:`aggregating API <basics.aggregate>`, :ref:`window API <window.overview>`, and :ref:`resample API <timeseries.aggregate>`.

An obvious one is aggregation via the :meth:`~pandas.core.groupby.DataFrameGroupBy.aggregate` or equivalently :meth:`~pandas.core.groupby.DataFrameGroupBy.agg` method:

.. ipython:: python

   grouped = df.groupby("A")
   grouped[["C", "D"]].aggregate(np.sum)

   grouped = df.groupby(["A", "B"])
   grouped.aggregate(np.sum)

As you can see, the result of the aggregation will have the group names as the new index along the grouped axis. In the case of multiple keys, the result is a :ref:`MultiIndex <advanced.hierarchical>` by default, though this can be changed by using the as_index option:

.. ipython:: python

   grouped = df.groupby(["A", "B"], as_index=False)
   grouped.aggregate(np.sum)

   df.groupby("A", as_index=False)[["C", "D"]].sum()

Note that you could use the reset_index DataFrame function to achieve the same result as the column names are stored in the resulting MultiIndex:

.. ipython:: python

   df.groupby(["A", "B"]).sum().reset_index()

Another simple aggregation example is to compute the size of each group. This is included in GroupBy as the size method. It returns a Series whose index are the group names and whose values are the sizes of each group.

.. ipython:: python

   grouped.size()

.. ipython:: python

   grouped.describe()

Another aggregation example is to compute the number of unique values of each group. This is similar to the value_counts function, except that it only counts unique values.

.. ipython:: python

   ll = [['foo', 1], ['foo', 2], ['foo', 2], ['bar', 1], ['bar', 1]]
   df4 = pd.DataFrame(ll, columns=["A", "B"])
   df4
   df4.groupby("A")["B"].nunique()

Note

Aggregation functions will not return the groups that you are aggregating over if they are named columns, when as_index=True, the default. The grouped columns will be the indices of the returned object.

Passing as_index=False will return the groups that you are aggregating over, if they are named columns.

Aggregating functions are the ones that reduce the dimension of the returned objects. Some common aggregating functions are tabulated below:

Function Description
:meth:`~pd.core.groupby.DataFrameGroupBy.mean` Compute mean of groups
:meth:`~pd.core.groupby.DataFrameGroupBy.sum` Compute sum of group values
:meth:`~pd.core.groupby.DataFrameGroupBy.size` Compute group sizes
:meth:`~pd.core.groupby.DataFrameGroupBy.count` Compute count of group
:meth:`~pd.core.groupby.DataFrameGroupBy.std` Standard deviation of groups
:meth:`~pd.core.groupby.DataFrameGroupBy.var` Compute variance of groups
:meth:`~pd.core.groupby.DataFrameGroupBy.sem` Standard error of the mean of groups
:meth:`~pd.core.groupby.DataFrameGroupBy.describe` Generates descriptive statistics
:meth:`~pd.core.groupby.DataFrameGroupBy.first` Compute first of group values
:meth:`~pd.core.groupby.DataFrameGroupBy.last` Compute last of group values
:meth:`~pd.core.groupby.DataFrameGroupBy.nth` Take nth value, or a subset if n is a list
:meth:`~pd.core.groupby.DataFrameGroupBy.min` Compute min of group values
:meth:`~pd.core.groupby.DataFrameGroupBy.max` Compute max of group values

The aggregating functions above will exclude NA values. Any function which reduces a :class:`Series` to a scalar value is an aggregation function and will work, a trivial example is df.groupby('A').agg(lambda ser: 1). Note that :meth:`~pd.core.groupby.DataFrameGroupBy.nth` can act as a reducer or a filter, see :ref:`here <groupby.nth>`.

Applying multiple functions at once

With grouped Series you can also pass a list or dict of functions to do aggregation with, outputting a DataFrame:

.. ipython:: python

   grouped = df.groupby("A")
   grouped["C"].agg([np.sum, np.mean, np.std])

On a grouped DataFrame, you can pass a list of functions to apply to each column, which produces an aggregated result with a hierarchical index:

.. ipython:: python

   grouped[["C", "D"]].agg([np.sum, np.mean, np.std])


The resulting aggregations are named for the functions themselves. If you need to rename, then you can add in a chained operation for a Series like this:

.. ipython:: python

   (
       grouped["C"]
       .agg([np.sum, np.mean, np.std])
       .rename(columns={"sum": "foo", "mean": "bar", "std": "baz"})
   )

For a grouped DataFrame, you can rename in a similar manner:

.. ipython:: python

   (
       grouped[["C", "D"]].agg([np.sum, np.mean, np.std]).rename(
           columns={"sum": "foo", "mean": "bar", "std": "baz"}
       )
   )

Note

In general, the output column names should be unique. You can't apply the same function (or two functions with the same name) to the same column.

.. ipython:: python
   :okexcept:

   grouped["C"].agg(["sum", "sum"])


pandas does allow you to provide multiple lambdas. In this case, pandas will mangle the name of the (nameless) lambda functions, appending _<i> to each subsequent lambda.

.. ipython:: python

   grouped["C"].agg([lambda x: x.max() - x.min(), lambda x: x.median() - x.mean()])

Named aggregation

.. versionadded:: 0.25.0

To support column-specific aggregation with control over the output column names, pandas accepts the special syntax in :meth:`DataFrameGroupBy.agg` and :meth:`SeriesGroupBy.agg`, known as "named aggregation", where

  • The keywords are the output column names
  • The values are tuples whose first element is the column to select and the second element is the aggregation to apply to that column. pandas provides the pandas.NamedAgg namedtuple with the fields ['column', 'aggfunc'] to make it clearer what the arguments are. As usual, the aggregation can be a callable or a string alias.
.. ipython:: python

   animals = pd.DataFrame(
       {
           "kind": ["cat", "dog", "cat", "dog"],
           "height": [9.1, 6.0, 9.5, 34.0],
           "weight": [7.9, 7.5, 9.9, 198.0],
       }
   )
   animals

   animals.groupby("kind").agg(
       min_height=pd.NamedAgg(column="height", aggfunc="min"),
       max_height=pd.NamedAgg(column="height", aggfunc="max"),
       average_weight=pd.NamedAgg(column="weight", aggfunc=np.mean),
   )


pandas.NamedAgg is just a namedtuple. Plain tuples are allowed as well.

.. ipython:: python

   animals.groupby("kind").agg(
       min_height=("height", "min"),
       max_height=("height", "max"),
       average_weight=("weight", np.mean),
   )


If your desired output column names are not valid Python keywords, construct a dictionary and unpack the keyword arguments

.. ipython:: python

   animals.groupby("kind").agg(
       **{
           "total weight": pd.NamedAgg(column="weight", aggfunc=sum)
       }
   )

Additional keyword arguments are not passed through to the aggregation functions. Only pairs of (column, aggfunc) should be passed as **kwargs. If your aggregation functions requires additional arguments, partially apply them with :meth:`functools.partial`.

Note

For Python 3.5 and earlier, the order of **kwargs in a functions was not preserved. This means that the output column ordering would not be consistent. To ensure consistent ordering, the keys (and so output columns) will always be sorted for Python 3.5.

Named aggregation is also valid for Series groupby aggregations. In this case there's no column selection, so the values are just the functions.

.. ipython:: python

   animals.groupby("kind").height.agg(
       min_height="min",
       max_height="max",
   )

Applying different functions to DataFrame columns

By passing a dict to aggregate you can apply a different aggregation to the columns of a DataFrame:

.. ipython:: python

   grouped.agg({"C": np.sum, "D": lambda x: np.std(x, ddof=1)})

The function names can also be strings. In order for a string to be valid it must be either implemented on GroupBy or available via :ref:`dispatching <groupby.dispatch>`:

.. ipython:: python

   grouped.agg({"C": "sum", "D": "std"})

Cython-optimized aggregation functions

Some common aggregations, currently only sum, mean, std, and sem, have optimized Cython implementations:

.. ipython:: python

   df.groupby("A")[["C", "D"]].sum()
   df.groupby(["A", "B"]).mean()

Of course sum and mean are implemented on pandas objects, so the above code would work even without the special versions via dispatching (see below).

Aggregations with User-Defined Functions

Users can also provide their own functions for custom aggregations. When aggregating with a User-Defined Function (UDF), the UDF should not mutate the provided Series, see :ref:`gotchas.udf-mutation` for more information.

.. ipython:: python

   animals.groupby("kind")[["height"]].agg(lambda x: set(x))

The resulting dtype will reflect that of the aggregating function. If the results from different groups have different dtypes, then a common dtype will be determined in the same way as DataFrame construction.

.. ipython:: python

   animals.groupby("kind")[["height"]].agg(lambda x: x.astype(int).sum())

Transformation

The transform method returns an object that is indexed the same as the one being grouped. The transform function must:

  • Return a result that is either the same size as the group chunk or broadcastable to the size of the group chunk (e.g., a scalar, grouped.transform(lambda x: x.iloc[-1])).
  • Operate column-by-column on the group chunk. The transform is applied to the first group chunk using chunk.apply.
  • Not perform in-place operations on the group chunk. Group chunks should be treated as immutable, and changes to a group chunk may produce unexpected results. For example, when using fillna, inplace must be False (grouped.transform(lambda x: x.fillna(inplace=False))).
  • (Optionally) operates on the entire group chunk. If this is supported, a fast path is used starting from the second chunk.
.. deprecated:: 1.5.0

    When using ``.transform`` on a grouped DataFrame and the transformation function
    returns a DataFrame, currently pandas does not align the result's index
    with the input's index. This behavior is deprecated and alignment will
    be performed in a future version of pandas. You can apply ``.to_numpy()`` to the
    result of the transformation function to avoid alignment.

Similar to :ref:`groupby.aggregate.udfs`, the resulting dtype will reflect that of the transformation function. If the results from different groups have different dtypes, then a common dtype will be determined in the same way as DataFrame construction.

Suppose we wished to standardize the data within each group:

.. ipython:: python

   index = pd.date_range("10/1/1999", periods=1100)
   ts = pd.Series(np.random.normal(0.5, 2, 1100), index)
   ts = ts.rolling(window=100, min_periods=100).mean().dropna()

   ts.head()
   ts.tail()

   transformed = ts.groupby(lambda x: x.year).transform(
       lambda x: (x - x.mean()) / x.std()
   )


We would expect the result to now have mean 0 and standard deviation 1 within each group, which we can easily check:

.. ipython:: python

   # Original Data
   grouped = ts.groupby(lambda x: x.year)
   grouped.mean()
   grouped.std()

   # Transformed Data
   grouped_trans = transformed.groupby(lambda x: x.year)
   grouped_trans.mean()
   grouped_trans.std()

We can also visually compare the original and transformed data sets.

.. ipython:: python

   compare = pd.DataFrame({"Original": ts, "Transformed": transformed})

   @savefig groupby_transform_plot.png
   compare.plot()

Transformation functions that have lower dimension outputs are broadcast to match the shape of the input array.

.. ipython:: python

   ts.groupby(lambda x: x.year).transform(lambda x: x.max() - x.min())

Alternatively, the built-in methods could be used to produce the same outputs.

.. ipython:: python

   max_ts = ts.groupby(lambda x: x.year).transform("max")
   min_ts = ts.groupby(lambda x: x.year).transform("min")

   max_ts - min_ts

Another common data transform is to replace missing data with the group mean.

.. ipython:: python
   :suppress:

   cols = ["A", "B", "C"]
   values = np.random.randn(1000, 3)
   values[np.random.randint(0, 1000, 100), 0] = np.nan
   values[np.random.randint(0, 1000, 50), 1] = np.nan
   values[np.random.randint(0, 1000, 200), 2] = np.nan
   data_df = pd.DataFrame(values, columns=cols)

.. ipython:: python

   data_df

   countries = np.array(["US", "UK", "GR", "JP"])
   key = countries[np.random.randint(0, 4, 1000)]

   grouped = data_df.groupby(key)

   # Non-NA count in each group
   grouped.count()

   transformed = grouped.transform(lambda x: x.fillna(x.mean()))

We can verify that the group means have not changed in the transformed data and that the transformed data contains no NAs.

.. ipython:: python

   grouped_trans = transformed.groupby(key)

   grouped.mean()  # original group means
   grouped_trans.mean()  # transformation did not change group means

   grouped.count()  # original has some missing data points
   grouped_trans.count()  # counts after transformation
   grouped_trans.size()  # Verify non-NA count equals group size

Note

Some functions will automatically transform the input when applied to a GroupBy object, but returning an object of the same shape as the original. Passing as_index=False will not affect these transformation methods.

For example: fillna, ffill, bfill, shift..

.. ipython:: python

   grouped.ffill()

Window and resample operations

It is possible to use resample(), expanding() and rolling() as methods on groupbys.

The example below will apply the rolling() method on the samples of the column B based on the groups of column A.

.. ipython:: python

   df_re = pd.DataFrame({"A": [1] * 10 + [5] * 10, "B": np.arange(20)})
   df_re

   df_re.groupby("A").rolling(4).B.mean()


The expanding() method will accumulate a given operation (sum() in the example) for all the members of each particular group.

.. ipython:: python

   df_re.groupby("A").expanding().sum()


Suppose you want to use the resample() method to get a daily frequency in each group of your dataframe and wish to complete the missing values with the ffill() method.

.. ipython:: python

   df_re = pd.DataFrame(
       {
           "date": pd.date_range(start="2016-01-01", periods=4, freq="W"),
           "group": [1, 1, 2, 2],
           "val": [5, 6, 7, 8],
       }
   ).set_index("date")
   df_re

   df_re.groupby("group").resample("1D").ffill()

Filtration

The filter method returns a subset of the original object. Suppose we want to take only elements that belong to groups with a group sum greater than 2.

.. ipython:: python

   sf = pd.Series([1, 1, 2, 3, 3, 3])
   sf.groupby(sf).filter(lambda x: x.sum() > 2)

The argument of filter must be a function that, applied to the group as a whole, returns True or False.

Another useful operation is filtering out elements that belong to groups with only a couple members.

.. ipython:: python

   dff = pd.DataFrame({"A": np.arange(8), "B": list("aabbbbcc")})
   dff.groupby("B").filter(lambda x: len(x) > 2)

Alternatively, instead of dropping the offending groups, we can return a like-indexed objects where the groups that do not pass the filter are filled with NaNs.

.. ipython:: python

   dff.groupby("B").filter(lambda x: len(x) > 2, dropna=False)

For DataFrames with multiple columns, filters should explicitly specify a column as the filter criterion.

.. ipython:: python

   dff["C"] = np.arange(8)
   dff.groupby("B").filter(lambda x: len(x["C"]) > 2)

Note

Some functions when applied to a groupby object will act as a filter on the input, returning a reduced shape of the original (and potentially eliminating groups), but with the index unchanged. Passing as_index=False will not affect these transformation methods.

For example: head, tail.

.. ipython:: python

   dff.groupby("B").head(2)

Dispatching to instance methods

When doing an aggregation or transformation, you might just want to call an instance method on each data group. This is pretty easy to do by passing lambda functions:

.. ipython:: python
   :okwarning:

   grouped = df.groupby("A")
   grouped.agg(lambda x: x.std())

But, it's rather verbose and can be untidy if you need to pass additional arguments. Using a bit of metaprogramming cleverness, GroupBy now has the ability to "dispatch" method calls to the groups:

.. ipython:: python
   :okwarning:

   grouped.std()

What is actually happening here is that a function wrapper is being generated. When invoked, it takes any passed arguments and invokes the function with any arguments on each group (in the above example, the std function). The results are then combined together much in the style of agg and transform (it actually uses apply to infer the gluing, documented next). This enables some operations to be carried out rather succinctly:

.. ipython:: python

   tsdf = pd.DataFrame(
       np.random.randn(1000, 3),
       index=pd.date_range("1/1/2000", periods=1000),
       columns=["A", "B", "C"],
   )
   tsdf.iloc[::2] = np.nan
   grouped = tsdf.groupby(lambda x: x.year)
   grouped.fillna(method="pad")

In this example, we chopped the collection of time series into yearly chunks then independently called :ref:`fillna <missing_data.fillna>` on the groups.

The nlargest and nsmallest methods work on Series style groupbys:

.. ipython:: python

   s = pd.Series([9, 8, 7, 5, 19, 1, 4.2, 3.3])
   g = pd.Series(list("abababab"))
   gb = s.groupby(g)
   gb.nlargest(3)
   gb.nsmallest(3)

Flexible apply

Some operations on the grouped data might not fit into either the aggregate or transform categories. Or, you may simply want GroupBy to infer how to combine the results. For these, use the apply function, which can be substituted for both aggregate and transform in many standard use cases. However, apply can handle some exceptional use cases.

Note

apply can act as a reducer, transformer, or filter function, depending on exactly what is passed to it. It can depend on the passed function and exactly what you are grouping. Thus the grouped column(s) may be included in the output as well as set the indices.

.. ipython:: python

   df
   grouped = df.groupby("A")

   # could also just call .describe()
   grouped["C"].apply(lambda x: x.describe())

The dimension of the returned result can also change:

.. ipython:: python

    grouped = df.groupby('A')['C']

    def f(group):
        return pd.DataFrame({'original': group,
                             'demeaned': group - group.mean()})
    grouped.apply(f)

apply on a Series can operate on a returned value from the applied function, that is itself a series, and possibly upcast the result to a DataFrame:

.. ipython:: python

    def f(x):
        return pd.Series([x, x ** 2], index=["x", "x^2"])


    s = pd.Series(np.random.rand(5))
    s
    s.apply(f)

Control grouped column(s) placement with group_keys

Note

If group_keys=True is specified when calling :meth:`~DataFrame.groupby`, functions passed to apply that return like-indexed outputs will have the group keys added to the result index. Previous versions of pandas would add the group keys only when the result from the applied function had a different index than the input. If group_keys is not specified, the group keys will not be added for like-indexed outputs. In the future this behavior will change to always respect group_keys, which defaults to True.

.. versionchanged:: 1.5.0

To control whether the grouped column(s) are included in the indices, you can use the argument group_keys. Compare

.. ipython:: python

    df.groupby("A", group_keys=True).apply(lambda x: x)

with

.. ipython:: python

    df.groupby("A", group_keys=False).apply(lambda x: x)

Similar to :ref:`groupby.aggregate.udfs`, the resulting dtype will reflect that of the apply function. If the results from different groups have different dtypes, then a common dtype will be determined in the same way as DataFrame construction.

Numba Accelerated Routines

.. versionadded:: 1.1

If Numba is installed as an optional dependency, the transform and aggregate methods support engine='numba' and engine_kwargs arguments. See :ref:`enhancing performance with Numba <enhancingperf.numba>` for general usage of the arguments and performance considerations.

The function signature must start with values, index exactly as the data belonging to each group will be passed into values, and the group index will be passed into index.

Warning

When using engine='numba', there will be no "fall back" behavior internally. The group data and group index will be passed as NumPy arrays to the JITed user defined function, and no alternative execution attempts will be tried.

Other useful features

Automatic exclusion of "nuisance" columns

Again consider the example DataFrame we've been looking at:

.. ipython:: python

   df

Suppose we wish to compute the standard deviation grouped by the A column. There is a slight problem, namely that we don't care about the data in column B. We refer to this as a "nuisance" column. You can avoid nuisance columns by specifying numeric_only=True:

.. ipython:: python

   df.groupby("A").std(numeric_only=True)

Note that df.groupby('A').colname.std(). is more efficient than df.groupby('A').std().colname, so if the result of an aggregation function is only interesting over one column (here colname), it may be filtered before applying the aggregation function.

Note

Any object column, also if it contains numerical values such as Decimal objects, is considered as a "nuisance" columns. They are excluded from aggregate functions automatically in groupby.

If you do wish to include decimal or object columns in an aggregation with other non-nuisance data types, you must do so explicitly.

Warning

The automatic dropping of nuisance columns has been deprecated and will be removed in a future version of pandas. If columns are included that cannot be operated on, pandas will instead raise an error. In order to avoid this, either select the columns you wish to operate on or specify numeric_only=True.

.. ipython:: python
    :okwarning:

    from decimal import Decimal

    df_dec = pd.DataFrame(
        {
            "id": [1, 2, 1, 2],
            "int_column": [1, 2, 3, 4],
            "dec_column": [
                Decimal("0.50"),
                Decimal("0.15"),
                Decimal("0.25"),
                Decimal("0.40"),
            ],
        }
    )

    # Decimal columns can be sum'd explicitly by themselves...
    df_dec.groupby(["id"])[["dec_column"]].sum()

    # ...but cannot be combined with standard data types or they will be excluded
    df_dec.groupby(["id"])[["int_column", "dec_column"]].sum()

    # Use .agg function to aggregate over standard and "nuisance" data types
    # at the same time
    df_dec.groupby(["id"]).agg({"int_column": "sum", "dec_column": "sum"})

Handling of (un)observed Categorical values

When using a Categorical grouper (as a single grouper, or as part of multiple groupers), the observed keyword controls whether to return a cartesian product of all possible groupers values (observed=False) or only those that are observed groupers (observed=True).

Show all values:

.. ipython:: python

   pd.Series([1, 1, 1]).groupby(
       pd.Categorical(["a", "a", "a"], categories=["a", "b"]), observed=False
   ).count()

Show only the observed values:

.. ipython:: python

   pd.Series([1, 1, 1]).groupby(
       pd.Categorical(["a", "a", "a"], categories=["a", "b"]), observed=True
   ).count()

The returned dtype of the grouped will always include all of the categories that were grouped.

.. ipython:: python

   s = (
       pd.Series([1, 1, 1])
       .groupby(pd.Categorical(["a", "a", "a"], categories=["a", "b"]), observed=False)
       .count()
   )
   s.index.dtype

NA and NaT group handling

If there are any NaN or NaT values in the grouping key, these will be automatically excluded. In other words, there will never be an "NA group" or "NaT group". This was not the case in older versions of pandas, but users were generally discarding the NA group anyway (and supporting it was an implementation headache).

Grouping with ordered factors

Categorical variables represented as instance of pandas's Categorical class can be used as group keys. If so, the order of the levels will be preserved:

.. ipython:: python

   data = pd.Series(np.random.randn(100))

   factor = pd.qcut(data, [0, 0.25, 0.5, 0.75, 1.0])

   data.groupby(factor).mean()

Grouping with a grouper specification

You may need to specify a bit more data to properly group. You can use the pd.Grouper to provide this local control.

.. ipython:: python

   import datetime

   df = pd.DataFrame(
       {
           "Branch": "A A A A A A A B".split(),
           "Buyer": "Carl Mark Carl Carl Joe Joe Joe Carl".split(),
           "Quantity": [1, 3, 5, 1, 8, 1, 9, 3],
           "Date": [
               datetime.datetime(2013, 1, 1, 13, 0),
               datetime.datetime(2013, 1, 1, 13, 5),
               datetime.datetime(2013, 10, 1, 20, 0),
               datetime.datetime(2013, 10, 2, 10, 0),
               datetime.datetime(2013, 10, 1, 20, 0),
               datetime.datetime(2013, 10, 2, 10, 0),
               datetime.datetime(2013, 12, 2, 12, 0),
               datetime.datetime(2013, 12, 2, 14, 0),
           ],
       }
   )

   df

Groupby a specific column with the desired frequency. This is like resampling.

.. ipython:: python

   df.groupby([pd.Grouper(freq="1M", key="Date"), "Buyer"])[["Quantity"]].sum()

You have an ambiguous specification in that you have a named index and a column that could be potential groupers.

.. ipython:: python

   df = df.set_index("Date")
   df["Date"] = df.index + pd.offsets.MonthEnd(2)
   df.groupby([pd.Grouper(freq="6M", key="Date"), "Buyer"])[["Quantity"]].sum()

   df.groupby([pd.Grouper(freq="6M", level="Date"), "Buyer"])[["Quantity"]].sum()


Taking the first rows of each group

Just like for a DataFrame or Series you can call head and tail on a groupby:

.. ipython:: python

   df = pd.DataFrame([[1, 2], [1, 4], [5, 6]], columns=["A", "B"])
   df

   g = df.groupby("A")
   g.head(1)

   g.tail(1)

This shows the first or last n rows from each group.

Taking the nth row of each group

To select from a DataFrame or Series the nth item, use :meth:`~pd.core.groupby.DataFrameGroupBy.nth`. This is a reduction method, and will return a single row (or no row) per group if you pass an int for n:

.. ipython:: python

   df = pd.DataFrame([[1, np.nan], [1, 4], [5, 6]], columns=["A", "B"])
   g = df.groupby("A")

   g.nth(0)
   g.nth(-1)
   g.nth(1)

If you want to select the nth not-null item, use the dropna kwarg. For a DataFrame this should be either 'any' or 'all' just like you would pass to dropna:

.. ipython:: python

   # nth(0) is the same as g.first()
   g.nth(0, dropna="any")
   g.first()

   # nth(-1) is the same as g.last()
   g.nth(-1, dropna="any")  # NaNs denote group exhausted when using dropna
   g.last()

   g.B.nth(0, dropna="all")

As with other methods, passing as_index=False, will achieve a filtration, which returns the grouped row.

.. ipython:: python

   df = pd.DataFrame([[1, np.nan], [1, 4], [5, 6]], columns=["A", "B"])
   g = df.groupby("A", as_index=False)

   g.nth(0)
   g.nth(-1)

You can also select multiple rows from each group by specifying multiple nth values as a list of ints.

.. ipython:: python

   business_dates = pd.date_range(start="4/1/2014", end="6/30/2014", freq="B")
   df = pd.DataFrame(1, index=business_dates, columns=["a", "b"])
   # get the first, 4th, and last date index for each month
   df.groupby([df.index.year, df.index.month]).nth([0, 3, -1])

Enumerate group items

To see the order in which each row appears within its group, use the cumcount method:

.. ipython:: python

   dfg = pd.DataFrame(list("aaabba"), columns=["A"])
   dfg

   dfg.groupby("A").cumcount()

   dfg.groupby("A").cumcount(ascending=False)

Enumerate groups

To see the ordering of the groups (as opposed to the order of rows within a group given by cumcount) you can use :meth:`~pandas.core.groupby.DataFrameGroupBy.ngroup`.

Note that the numbers given to the groups match the order in which the groups would be seen when iterating over the groupby object, not the order they are first observed.

.. ipython:: python

   dfg = pd.DataFrame(list("aaabba"), columns=["A"])
   dfg

   dfg.groupby("A").ngroup()

   dfg.groupby("A").ngroup(ascending=False)

Plotting

Groupby also works with some plotting methods. For example, suppose we suspect that some features in a DataFrame may differ by group, in this case, the values in column 1 where the group is "B" are 3 higher on average.

.. ipython:: python

   np.random.seed(1234)
   df = pd.DataFrame(np.random.randn(50, 2))
   df["g"] = np.random.choice(["A", "B"], size=50)
   df.loc[df["g"] == "B", 1] += 3

We can easily visualize this with a boxplot:

.. ipython:: python
   :okwarning:

   @savefig groupby_boxplot.png
   df.groupby("g").boxplot()

The result of calling boxplot is a dictionary whose keys are the values of our grouping column g ("A" and "B"). The values of the resulting dictionary can be controlled by the return_type keyword of boxplot. See the :ref:`visualization documentation<visualization.box>` for more.

Warning

For historical reasons, df.groupby("g").boxplot() is not equivalent to df.boxplot(by="g"). See :ref:`here<visualization.box.return>` for an explanation.

Piping function calls

Similar to the functionality provided by DataFrame and Series, functions that take GroupBy objects can be chained together using a pipe method to allow for a cleaner, more readable syntax. To read about .pipe in general terms, see :ref:`here <basics.pipe>`.

Combining .groupby and .pipe is often useful when you need to reuse GroupBy objects.

As an example, imagine having a DataFrame with columns for stores, products, revenue and quantity sold. We'd like to do a groupwise calculation of prices (i.e. revenue/quantity) per store and per product. We could do this in a multi-step operation, but expressing it in terms of piping can make the code more readable. First we set the data:

.. ipython:: python

   n = 1000
   df = pd.DataFrame(
       {
           "Store": np.random.choice(["Store_1", "Store_2"], n),
           "Product": np.random.choice(["Product_1", "Product_2"], n),
           "Revenue": (np.random.random(n) * 50 + 10).round(2),
           "Quantity": np.random.randint(1, 10, size=n),
       }
   )
   df.head(2)

Now, to find prices per store/product, we can simply do:

.. ipython:: python

   (
       df.groupby(["Store", "Product"])
       .pipe(lambda grp: grp.Revenue.sum() / grp.Quantity.sum())
       .unstack()
       .round(2)
   )

Piping can also be expressive when you want to deliver a grouped object to some arbitrary function, for example:

.. ipython:: python

   def mean(groupby):
       return groupby.mean()


   df.groupby(["Store", "Product"]).pipe(mean)

where mean takes a GroupBy object and finds the mean of the Revenue and Quantity columns respectively for each Store-Product combination. The mean function can be any function that takes in a GroupBy object; the .pipe will pass the GroupBy object as a parameter into the function you specify.

Examples

Regrouping by factor

Regroup columns of a DataFrame according to their sum, and sum the aggregated ones.

.. ipython:: python

   df = pd.DataFrame({"a": [1, 0, 0], "b": [0, 1, 0], "c": [1, 0, 0], "d": [2, 3, 4]})
   df
   df.groupby(df.sum(), axis=1).sum()

Multi-column factorization

By using :meth:`~pandas.core.groupby.DataFrameGroupBy.ngroup`, we can extract information about the groups in a way similar to :func:`factorize` (as described further in the :ref:`reshaping API <reshaping.factorize>`) but which applies naturally to multiple columns of mixed type and different sources. This can be useful as an intermediate categorical-like step in processing, when the relationships between the group rows are more important than their content, or as input to an algorithm which only accepts the integer encoding. (For more information about support in pandas for full categorical data, see the :ref:`Categorical introduction <categorical>` and the :ref:`API documentation <api.arrays.categorical>`.)

.. ipython:: python

    dfg = pd.DataFrame({"A": [1, 1, 2, 3, 2], "B": list("aaaba")})

    dfg

    dfg.groupby(["A", "B"]).ngroup()

    dfg.groupby(["A", [0, 0, 0, 1, 1]]).ngroup()

Groupby by indexer to 'resample' data

Resampling produces new hypothetical samples (resamples) from already existing observed data or from a model that generates data. These new samples are similar to the pre-existing samples.

In order to resample to work on indices that are non-datetimelike, the following procedure can be utilized.

In the following examples, df.index // 5 returns a binary array which is used to determine what gets selected for the groupby operation.

Note

The below example shows how we can downsample by consolidation of samples into fewer samples. Here by using df.index // 5, we are aggregating the samples in bins. By applying std() function, we aggregate the information contained in many samples into a small subset of values which is their standard deviation thereby reducing the number of samples.

.. ipython:: python

   df = pd.DataFrame(np.random.randn(10, 2))
   df
   df.index // 5
   df.groupby(df.index // 5).std()

Returning a Series to propagate names

Group DataFrame columns, compute a set of metrics and return a named Series. The Series name is used as the name for the column index. This is especially useful in conjunction with reshaping operations such as stacking in which the column index name will be used as the name of the inserted column:

.. ipython:: python

   df = pd.DataFrame(
       {
           "a": [0, 0, 0, 0, 1, 1, 1, 1, 2, 2, 2, 2],
           "b": [0, 0, 1, 1, 0, 0, 1, 1, 0, 0, 1, 1],
           "c": [1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0],
           "d": [0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1],
       }
   )

   def compute_metrics(x):
       result = {"b_sum": x["b"].sum(), "c_mean": x["c"].mean()}
       return pd.Series(result, name="metrics")

   result = df.groupby("a").apply(compute_metrics)

   result

   result.stack()