How to get request's path with parameter not substituted?

[andrii-korotkov-verkada]

Hello,
I hope your day is going well.
I'm working with Flask endpoints that have parameters, e.g. @app.route("/prefix/<param>", methods=["GET"]). Suppose param can be a string. I'm looking for a way to access a current route's parametrized path, i.e. /prefix/<param>, not /prefix/abc. How can I do that? What would request.path return?
Thank you.

[davidism]

request.url_rul contains the matched Rule object https://werkzeug.palletsprojects.com/en/3.0.x/routing/#werkzeug.routing.Rule

[andrii-korotkov-verkada]

Thank you! url_rule is the answer.