Inertia - Status code on exception

[Xstoudi]

Hey, the inertia doc mention this:

use Illuminate\Http\Request;
use Symfony\Component\HttpFoundation\Response;
use Inertia\Inertia;

->withExceptions(function (Exceptions $exceptions) {
    $exceptions->respond(function (Response $response, Throwable $exception, Request $request) {
        if (! app()->environment(['local', 'testing']) && in_array($response->getStatusCode(), [500, 503, 404, 403])) {
            return Inertia::render('Error', ['status' => $response->getStatusCode()])
                ->toResponse($request)
                ->setStatusCode($response->getStatusCode());
        } elseif ($response->getStatusCode() === 419) {
            return back()->with([
                'message' => 'The page expired, please try again.',
            ]);
        }

        return $response;
    });
})

What would be the recommended way to return, for example, a 404 status code?

[Julien-R44]

If you're using the inertia starter-kit then it's handled automatically for you in the Exception Handler. See there : https://github.com/adonisjs/inertia-starter-kit/blob/main/app/exceptions/handler.ts#L24

If you throw an exception with a 404 status code, your error page will be rendered with Inertia. For example, this is the case with Lucid's findxxOrFail methods:

export default class UsersController {
  async index({ inertia, response }: HttpContext) {
    const user = await User.findOrFail(1212121);

    // ...
  }
}

If the user is not found, then :

• The exception E_ROW_NOT_FOUND will be thrown. This same E_ROW_NOT_FOUND exception uses a status code 404 as seen in the linked code.
• We enter the exception handler with this exception that has just been thrown
• The exception handler will apply the status page rendering logic according to the status code
• Then we finally call the inertia.render which will render your error page via inertia