Filter for output of specific commands

[reknih]

Description: Allow me to filter which command outputs I want to display. Still run all tasks.

Use case: I want to debug a particular task of the set of tasks I run with concurrently and focus on its outputs. At the moment, I solve this by calling npm run dev | grep name-of-task. This works but potentially includes false positives. Additionally, concurrently will not color the task name because it is not directly attached to the terminal.

[gustavohenke]

How does the existing --hide flag work for you?

[amannn]

I have a similar situation. I have two processes and would like to use --hide 1 --raw, so that only the output from the first process is displayed. Unfortunately, --raw seems to ignore any --hide argument.

Would it make sense to support this?

[gustavohenke]

Yes, but note that raw mode implies inheriting stdio, which means no control over the output.

concurrently/src/get-spawn-opts.ts

Line 42 in a61ef39

...(raw && { stdio: 'inherit' as const }),

It might be possible to change it to ignore instead of inherit to support your use case.

[reknih]

How does the existing --hide flag work for you?

It works I guess but I run many tasks, so it's much easier to list the task I want to see instead of every other task.