Expose the name of the currently called item

[SergioBenitez]

Corollary to #146: so you can retrieve the dynamic name without having to clone it into the filter/function/test.

[mitsuhiko]

In a way this also would need to go into FastRecurse and FastSuper since there is a peephole optimization for these basic loop() and super() calls that immediately render.

At the same time those calls infos would only be observable by the engine itself, so paying the extra cost for that seems pointless?

So I think this either should be fixed or a comment should be left in FastRecurse and FastSuper about why they don't update the current call.

[mitsuhiko]

This would need to do something like let old_call = mem::replace(&mut state.current_call, Some(name)); since you can have things like {{ foo.bar(blub.blah()) }}.

[SergioBenitez]

I believe this should just work as-is since foo.bar(blub.blah()) is really:

call blub.blah
pop
call foo.bar

I'll write some tests to confirm.

[SergioBenitez]

Confirmed (no bug) via tests. This change also means you can get rid of the name argument in Object::call_method() if the unwrap() (which should always succeed) is acceptable.

[SergioBenitez]

In a way this also would need to go into FastRecurse and FastSuper since there is a peephole optimization for these basic loop() and super() calls that immediately render.

At the same time those calls infos would only be observable by the engine itself, so paying the extra cost for that seems pointless?

So I think this either should be fixed or a comment should be left in FastRecurse and FastSuper about why they don't update the current call.

Indeed, I didn't update the state where it's only visible internally since it provides no value. I'll leave a comment.