uncalledFunctionChecksInConditional.errors.txt

tests/cases/compiler/uncalledFunctionChecksInConditional.ts(5,5): error TS2774: This condition will always return true since this function is always defined. Did you mean to call it instead?
tests/cases/compiler/uncalledFunctionChecksInConditional.ts(9,5): error TS2774: This condition will always return true since this function is always defined. Did you mean to call it instead?
tests/cases/compiler/uncalledFunctionChecksInConditional.ts(9,14): error TS2774: This condition will always return true since this function is always defined. Did you mean to call it instead?
tests/cases/compiler/uncalledFunctionChecksInConditional.ts(13,5): error TS2774: This condition will always return true since this function is always defined. Did you mean to call it instead?
tests/cases/compiler/uncalledFunctionChecksInConditional.ts(32,10): error TS2774: This condition will always return true since this function is always defined. Did you mean to call it instead?
tests/cases/compiler/uncalledFunctionChecksInConditional.ts(36,5): error TS2774: This condition will always return true since this function is always defined. Did you mean to call it instead?
tests/cases/compiler/uncalledFunctionChecksInConditional.ts(40,22): error TS2774: This condition will always return true since this function is always defined. Did you mean to call it instead?
tests/cases/compiler/uncalledFunctionChecksInConditional.ts(44,16): error TS2774: This condition will always return true since this function is always defined. Did you mean to call it instead?
tests/cases/compiler/uncalledFunctionChecksInConditional.ts(48,22): error TS2774: This condition will always return true since this function is always defined. Did you mean to call it instead?


==== tests/cases/compiler/uncalledFunctionChecksInConditional.ts (9 errors) ====
    declare function isFoo(): boolean;
    declare function isBar(): boolean;
    declare const isUndefinedFoo: (() => boolean) | undefined;
    
    if (isFoo) {
        ~~~~~
!!! error TS2774: This condition will always return true since this function is always defined. Did you mean to call it instead?
        // error on isFoo
    }
    
    if (isFoo || isBar) {
        ~~~~~
!!! error TS2774: This condition will always return true since this function is always defined. Did you mean to call it instead?
                 ~~~~~
!!! error TS2774: This condition will always return true since this function is always defined. Did you mean to call it instead?
        // error on isFoo, isBar
    }
    
    if (isFoo || isFoo()) {
        ~~~~~
!!! error TS2774: This condition will always return true since this function is always defined. Did you mean to call it instead?
        // error on isFoo
    }
    
    if (isUndefinedFoo || isFoo()) {
        // no error
    }
    
    if (isFoo && isFoo()) {
        // no error
    }
    
    declare const x: boolean;
    declare const ux: boolean | undefined;
    declare const y: boolean;
    declare const uy: boolean | undefined;
    declare function z(): boolean;
    declare const uz: (() => boolean) | undefined;
    
    if (x || isFoo) {
             ~~~~~
!!! error TS2774: This condition will always return true since this function is always defined. Did you mean to call it instead?
        // error on isFoo
    }
    
    if (isFoo || x) {
        ~~~~~
!!! error TS2774: This condition will always return true since this function is always defined. Did you mean to call it instead?
        // error on isFoo
    }
    
    if (x || y || z() || isFoo) {
                         ~~~~~
!!! error TS2774: This condition will always return true since this function is always defined. Did you mean to call it instead?
        // error on isFoo
    }
    
    if (x || uy || z || isUndefinedFoo) {
                   ~
!!! error TS2774: This condition will always return true since this function is always defined. Did you mean to call it instead?
        // error on z
    }
    
    if (ux || y || uz || isFoo) {
                         ~~~~~
!!! error TS2774: This condition will always return true since this function is always defined. Did you mean to call it instead?
        // error on isFoo
    }
    
    if (x && z) {
        // no error
        z();
    }