Call fake.zipcode_in_state('AZ'), the return zipcode not valid AZ zip code

[pengdada00100]

• Faker version: 24.0
• OS:Macos

Call fake.zipcode_in_state('AZ'), the return zipcode not valid AZ zip code

Steps to reproduce

Run code:
`from faker import Faker

if name == "main":
fake = Faker()
f = fake.zipcode_in_state('AZ')
print(f)`

get 85800 which not in AZ state

Expected behavior

The zip code should in AZ

Actual behavior

The zipcode not in AZ

[stefan6419846]

The implementation is in

faker/faker/providers/address/en_US/__init__.py

Lines 543 to 547 in 250fa19

	self.generator.random.randint(
	self.states_postcode[state_abbr][0],
	self.states_postcode[state_abbr][1],
	)
	)

Feel free to submit a corresponding PR.

[lozik4]

• Faker version: 24.0
• OS:Macos

Call fake.zipcode_in_state('AZ'), the return zipcode not valid AZ zip code

Steps to reproduce

Run code: `from faker import Faker

if name == "main": fake = Faker() f = fake.zipcode_in_state('AZ') print(f)`

get 85800 which not in AZ state

Expected behavior

The zip code should in AZ

Actual behavior

The zipcode not in AZ

@pengdada00100
You can add locale to your code
For example:

if __name__ == "__main__":
    fake = Faker("en_US") # add locale
    f = fake.zipcode_in_state('AZ')
    print(f)

[tonyk232]

I think this issue can be closed. The problem is that not all 5 digits are valid ZIP codes, and faker can't create valid ones without checking them from a database/API.

However, 85775 is Tucson, AZ and 85901 is Show Low, AZ, so the randomly created 85800 is in the correct range for AZ.