[Rust] Way to copy/access a tables' buffer from a generated type

[dsxmachina]

Hello,

I just recently tried to update from the Rust flatbuffer Version 2.1.2 to the newest 22.10.26.
However, one change kind of broke my entire design:

In 2.1.2 the buf: &'a [u8] field inside the Table struct was public.
So you could easily create a real copy of your Flatbuffer-Object, just by cloning the inner table:

fn encode(&self) -> Bytes {
  Bytes::copy_from_slice(self._tab.buf)
}

Here I "encode" a generated flatbuffer object, so I have a Vec<u8> or in this case Bytes Object,
which I can freely move around (as it lives on the heap), and reinterpret as my flatbuffer type with

root_unchecked::<MyType>( bytes )

Which is kind of nice, as it allows me to move the flatbuffer objects around and pass copies of it to functions pretty easy.

However - in 22.10.26 this is not possible anymore, and I am wondering why, because I really miss the feature of getting access to the underlying buffer object.
Am I missing an obvious way of how you should handle these objects ?

Would it be possible to re-add the old interface ?
(Maybe the field does not need to be public, but instead a getter-function to the inner buffer ?)
I would happily create a pull request, if this is desired.

Please let me know, and keep up your amazing work with this project.
Thank you !

[enum-class]

Please check this links, maybe helps:
#7700
3be296e

[dsxmachina]

Nice - this should solve it :).
Out of curiosity - do you have any Idea when this will be released ?
In https://crates.io/crates/flatbuffers the Version is still at 22.10.26 - the commit that fixes it comes after that.

[dsxmachina]

Anyway, the issue can be closed.
If you have any information regarding the release, please let me know.