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FindFirstAndLastPosition.java
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FindFirstAndLastPosition.java
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/**
* 34. Find first and Last Position of Element in Sorted Array.
* 二分查找。细节满满。
* 需要注意,在二分法逼近的时候,分两种情况:
* 1. left = mid+1, right = mid. 这种逼近的时候,rihgt不会主动向左逼近,为了防止死循环,mid需要向下取整(偏左)。
* 2. left = mid, right = mid - 1. 这种逼近的时候,left不会主动向右逼近,为了防止死循环,mid需要向上取整(偏右)。
* @author LBW
*/
public class FindFirstAndLastPosition {
public int[] searchRange(int[] nums, int target) {
if (nums.length == 0)
return new int[]{-1, -1};
int left = findLeft(nums, target);
if (left == -1)
return new int[]{-1, -1};
int right = findRight(nums, target);
return new int[]{left, right};
}
private int findLeft(int[] nums, int target) {
int n = nums.length;
if (n == 0)
return -1;
int left = 0, right = n - 1;
while (left < right) {
int mid = (left + right) / 2;
if (nums[mid] < target) {
left = mid + 1;
}
else if (nums[mid] == target) {
right = mid;
}
else {
right = mid - 1;
}
}
if (nums[left] == target)
return left;
return -1;
}
private int findRight(int[] nums, int target) {
int n = nums.length;
int left = 0, right = n - 1;
while (left < right) {
int mid = (left + right + 1) / 2;
if (nums[mid] > target) {
right = mid - 1;
}
else if (nums[mid] == target) {
left = mid;
}
else {
left = mid + 1;
}
}
if (nums[left] == target)
return left;
return -1;
}
public static void main(String[] args) {
int[] nums = new int[]{5, 7, 7, 8, 8, 10};
FindFirstAndLastPosition findFirstAndLastPosition = new FindFirstAndLastPosition();
findFirstAndLastPosition.searchRange(nums, 8);
}
//老办法。递归。
private int findLeftTarget(int[] nums, int l, int r, int target) {
if (l > r || (l == r && nums[l] != target))
return -1;
else if (l == r) {
return l;
}
int mid = (l + r) / 2;
if (nums[mid] > target) {
return findLeftTarget(nums, l, mid-1, target);
}
else if (nums[mid] < target) {
return findLeftTarget(nums, mid+1, r, target);
}
else {
return findLeftTarget(nums, l, mid, target);
}
}
private int findRightTarget(int[] nums, int l, int r, int target) {
if (l > r || (l == r && nums[l] != target))
return -1;
else if (l == r)
return r;
int mid = (l + r + 1) / 2;
if (nums[mid] > target) {
return findRightTarget(nums, l, mid-1, target);
}
else if (nums[mid] < target) {
return findRightTarget(nums, mid+1, r, target);
}
else {
return findRightTarget(nums, mid, r, target);
}
}
}