adjacent-overload-signatures.md

description
Require that member overloads be consecutive.

🛑 This file is source code, not the primary documentation location! 🛑

See https://typescript-eslint.io/rules/adjacent-overload-signatures for documentation.

Grouping overloaded members together can improve readability of the code.

Rule Details

This rule aims to standardize the way overloaded members are organized.

❌ Incorrect

declare namespace Foo {
  export function foo(s: string): void;
  export function foo(n: number): void;
  export function bar(): void;
  export function foo(sn: string | number): void;
}

type Foo = {
  foo(s: string): void;
  foo(n: number): void;
  bar(): void;
  foo(sn: string | number): void;
};

interface Foo {
  foo(s: string): void;
  foo(n: number): void;
  bar(): void;
  foo(sn: string | number): void;
}

class Foo {
  foo(s: string): void;
  foo(n: number): void;
  bar(): void {}
  foo(sn: string | number): void {}
}

export function foo(s: string): void;
export function foo(n: number): void;
export function bar(): void;
export function foo(sn: string | number): void;

✅ Correct

declare namespace Foo {
  export function foo(s: string): void;
  export function foo(n: number): void;
  export function foo(sn: string | number): void;
  export function bar(): void;
}

type Foo = {
  foo(s: string): void;
  foo(n: number): void;
  foo(sn: string | number): void;
  bar(): void;
};

interface Foo {
  foo(s: string): void;
  foo(n: number): void;
  foo(sn: string | number): void;
  bar(): void;
}

class Foo {
  foo(s: string): void;
  foo(n: number): void;
  foo(sn: string | number): void {}
  bar(): void {}
}

export function bar(): void;
export function foo(s: string): void;
export function foo(n: number): void;
export function foo(sn: string | number): void;

Options

// .eslintrc.json
{
  "rules": {
    "@typescript-eslint/adjacent-overload-signatures": "error"
  }
}

This rule is not configurable.

When Not To Use It

If you don't care about the general structure of the code, then you will not need this rule.