[Question] how do I create a BStr from &[u8] ?

[jtmoon79]

Newbie question: how do I create a bstr::BStr instance from a &[u8]?

Given let a: [u8; 3] = [ 40, 46, 55 ];, I've tried variations

• bstr::BStr::From::<&[u8]>(&a)
• bstr::BStr::From(&a)
• bstr::BStr::From(a)
• bstr::BStr::new(&a)
• bstr::BStr::from_bytes(&a)

I reviewed the docs and it wasn't obvious to this rust newbie.

[lopopolo]

I think this is how you're meant to do it:

use bstr::ByteSlice;

let a = [0_u8; 3];
let b = a.as_bstr();

Most of the APIs in this crate come from either ByteSlice or ByteVec. These are extension traits, which means when they are imported, they make methods available on vecs and slices that bstr implements these traits on.

[BurntSushi]

It's also worth pointing out that you don't actually have a byte slice here. You have an array of bytes. It's likely we could improve the from impls with const generics.

[BurntSushi]

For const generics, see #86. Otherwise moving this to a Discussion Q&A.